3.21 \(\int x^2 (d+i c d x)^3 (a+b \tan ^{-1}(c x)) \, dx\)

Optimal. Leaf size=191 \[ -\frac {1}{6} i c^3 d^3 x^6 \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{5} c^2 d^3 x^5 \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{4} i c d^3 x^4 \left (a+b \tan ^{-1}(c x)\right )+\frac {1}{3} d^3 x^3 \left (a+b \tan ^{-1}(c x)\right )-\frac {11 i b d^3 \tan ^{-1}(c x)}{12 c^3}+\frac {1}{30} i b c^2 d^3 x^5+\frac {11 i b d^3 x}{12 c^2}+\frac {7 b d^3 \log \left (c^2 x^2+1\right )}{15 c^3}+\frac {3}{20} b c d^3 x^4-\frac {7 b d^3 x^2}{15 c}-\frac {11}{36} i b d^3 x^3 \]

[Out]

11/12*I*b*d^3*x/c^2-7/15*b*d^3*x^2/c-11/36*I*b*d^3*x^3+3/20*b*c*d^3*x^4+1/30*I*b*c^2*d^3*x^5-11/12*I*b*d^3*arc
tan(c*x)/c^3+1/3*d^3*x^3*(a+b*arctan(c*x))+3/4*I*c*d^3*x^4*(a+b*arctan(c*x))-3/5*c^2*d^3*x^5*(a+b*arctan(c*x))
-1/6*I*c^3*d^3*x^6*(a+b*arctan(c*x))+7/15*b*d^3*ln(c^2*x^2+1)/c^3

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Rubi [A]  time = 0.17, antiderivative size = 191, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.304, Rules used = {43, 4872, 12, 1802, 635, 203, 260} \[ -\frac {1}{6} i c^3 d^3 x^6 \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{5} c^2 d^3 x^5 \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{4} i c d^3 x^4 \left (a+b \tan ^{-1}(c x)\right )+\frac {1}{3} d^3 x^3 \left (a+b \tan ^{-1}(c x)\right )+\frac {1}{30} i b c^2 d^3 x^5+\frac {7 b d^3 \log \left (c^2 x^2+1\right )}{15 c^3}+\frac {11 i b d^3 x}{12 c^2}-\frac {11 i b d^3 \tan ^{-1}(c x)}{12 c^3}+\frac {3}{20} b c d^3 x^4-\frac {7 b d^3 x^2}{15 c}-\frac {11}{36} i b d^3 x^3 \]

Antiderivative was successfully verified.

[In]

Int[x^2*(d + I*c*d*x)^3*(a + b*ArcTan[c*x]),x]

[Out]

(((11*I)/12)*b*d^3*x)/c^2 - (7*b*d^3*x^2)/(15*c) - ((11*I)/36)*b*d^3*x^3 + (3*b*c*d^3*x^4)/20 + (I/30)*b*c^2*d
^3*x^5 - (((11*I)/12)*b*d^3*ArcTan[c*x])/c^3 + (d^3*x^3*(a + b*ArcTan[c*x]))/3 + ((3*I)/4)*c*d^3*x^4*(a + b*Ar
cTan[c*x]) - (3*c^2*d^3*x^5*(a + b*ArcTan[c*x]))/5 - (I/6)*c^3*d^3*x^6*(a + b*ArcTan[c*x]) + (7*b*d^3*Log[1 +
c^2*x^2])/(15*c^3)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 260

Int[(x_)^(m_.)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[Log[RemoveContent[a + b*x^n, x]]/(b*n), x] /; FreeQ
[{a, b, m, n}, x] && EqQ[m, n - 1]

Rule 635

Int[((d_) + (e_.)*(x_))/((a_) + (c_.)*(x_)^2), x_Symbol] :> Dist[d, Int[1/(a + c*x^2), x], x] + Dist[e, Int[x/
(a + c*x^2), x], x] /; FreeQ[{a, c, d, e}, x] &&  !NiceSqrtQ[-(a*c)]

Rule 1802

Int[(Pq_)*((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*Pq*(a + b*x
^2)^p, x], x] /; FreeQ[{a, b, c, m}, x] && PolyQ[Pq, x] && IGtQ[p, -2]

Rule 4872

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_.)*((d_.) + (e_.)*(x_))^(q_.), x_Symbol] :> With[{u = I
ntHide[(f*x)^m*(d + e*x)^q, x]}, Dist[a + b*ArcTan[c*x], u, x] - Dist[b*c, Int[SimplifyIntegrand[u/(1 + c^2*x^
2), x], x], x]] /; FreeQ[{a, b, c, d, e, f, q}, x] && NeQ[q, -1] && IntegerQ[2*m] && ((IGtQ[m, 0] && IGtQ[q, 0
]) || (ILtQ[m + q + 1, 0] && LtQ[m*q, 0]))

Rubi steps

\begin {align*} \int x^2 (d+i c d x)^3 \left (a+b \tan ^{-1}(c x)\right ) \, dx &=\frac {1}{3} d^3 x^3 \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{4} i c d^3 x^4 \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{5} c^2 d^3 x^5 \left (a+b \tan ^{-1}(c x)\right )-\frac {1}{6} i c^3 d^3 x^6 \left (a+b \tan ^{-1}(c x)\right )-(b c) \int \frac {d^3 x^3 \left (20+45 i c x-36 c^2 x^2-10 i c^3 x^3\right )}{60 \left (1+c^2 x^2\right )} \, dx\\ &=\frac {1}{3} d^3 x^3 \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{4} i c d^3 x^4 \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{5} c^2 d^3 x^5 \left (a+b \tan ^{-1}(c x)\right )-\frac {1}{6} i c^3 d^3 x^6 \left (a+b \tan ^{-1}(c x)\right )-\frac {1}{60} \left (b c d^3\right ) \int \frac {x^3 \left (20+45 i c x-36 c^2 x^2-10 i c^3 x^3\right )}{1+c^2 x^2} \, dx\\ &=\frac {1}{3} d^3 x^3 \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{4} i c d^3 x^4 \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{5} c^2 d^3 x^5 \left (a+b \tan ^{-1}(c x)\right )-\frac {1}{6} i c^3 d^3 x^6 \left (a+b \tan ^{-1}(c x)\right )-\frac {1}{60} \left (b c d^3\right ) \int \left (-\frac {55 i}{c^3}+\frac {56 x}{c^2}+\frac {55 i x^2}{c}-36 x^3-10 i c x^4+\frac {55 i-56 c x}{c^3 \left (1+c^2 x^2\right )}\right ) \, dx\\ &=\frac {11 i b d^3 x}{12 c^2}-\frac {7 b d^3 x^2}{15 c}-\frac {11}{36} i b d^3 x^3+\frac {3}{20} b c d^3 x^4+\frac {1}{30} i b c^2 d^3 x^5+\frac {1}{3} d^3 x^3 \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{4} i c d^3 x^4 \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{5} c^2 d^3 x^5 \left (a+b \tan ^{-1}(c x)\right )-\frac {1}{6} i c^3 d^3 x^6 \left (a+b \tan ^{-1}(c x)\right )-\frac {\left (b d^3\right ) \int \frac {55 i-56 c x}{1+c^2 x^2} \, dx}{60 c^2}\\ &=\frac {11 i b d^3 x}{12 c^2}-\frac {7 b d^3 x^2}{15 c}-\frac {11}{36} i b d^3 x^3+\frac {3}{20} b c d^3 x^4+\frac {1}{30} i b c^2 d^3 x^5+\frac {1}{3} d^3 x^3 \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{4} i c d^3 x^4 \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{5} c^2 d^3 x^5 \left (a+b \tan ^{-1}(c x)\right )-\frac {1}{6} i c^3 d^3 x^6 \left (a+b \tan ^{-1}(c x)\right )-\frac {\left (11 i b d^3\right ) \int \frac {1}{1+c^2 x^2} \, dx}{12 c^2}+\frac {\left (14 b d^3\right ) \int \frac {x}{1+c^2 x^2} \, dx}{15 c}\\ &=\frac {11 i b d^3 x}{12 c^2}-\frac {7 b d^3 x^2}{15 c}-\frac {11}{36} i b d^3 x^3+\frac {3}{20} b c d^3 x^4+\frac {1}{30} i b c^2 d^3 x^5-\frac {11 i b d^3 \tan ^{-1}(c x)}{12 c^3}+\frac {1}{3} d^3 x^3 \left (a+b \tan ^{-1}(c x)\right )+\frac {3}{4} i c d^3 x^4 \left (a+b \tan ^{-1}(c x)\right )-\frac {3}{5} c^2 d^3 x^5 \left (a+b \tan ^{-1}(c x)\right )-\frac {1}{6} i c^3 d^3 x^6 \left (a+b \tan ^{-1}(c x)\right )+\frac {7 b d^3 \log \left (1+c^2 x^2\right )}{15 c^3}\\ \end {align*}

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Mathematica [A]  time = 0.09, size = 234, normalized size = 1.23 \[ -\frac {1}{6} i a c^3 d^3 x^6-\frac {3}{5} a c^2 d^3 x^5+\frac {3}{4} i a c d^3 x^4+\frac {1}{3} a d^3 x^3-\frac {1}{6} i b c^3 d^3 x^6 \tan ^{-1}(c x)-\frac {11 i b d^3 \tan ^{-1}(c x)}{12 c^3}+\frac {1}{30} i b c^2 d^3 x^5-\frac {3}{5} b c^2 d^3 x^5 \tan ^{-1}(c x)+\frac {11 i b d^3 x}{12 c^2}+\frac {7 b d^3 \log \left (c^2 x^2+1\right )}{15 c^3}+\frac {3}{20} b c d^3 x^4+\frac {3}{4} i b c d^3 x^4 \tan ^{-1}(c x)+\frac {1}{3} b d^3 x^3 \tan ^{-1}(c x)-\frac {7 b d^3 x^2}{15 c}-\frac {11}{36} i b d^3 x^3 \]

Antiderivative was successfully verified.

[In]

Integrate[x^2*(d + I*c*d*x)^3*(a + b*ArcTan[c*x]),x]

[Out]

(((11*I)/12)*b*d^3*x)/c^2 - (7*b*d^3*x^2)/(15*c) + (a*d^3*x^3)/3 - ((11*I)/36)*b*d^3*x^3 + ((3*I)/4)*a*c*d^3*x
^4 + (3*b*c*d^3*x^4)/20 - (3*a*c^2*d^3*x^5)/5 + (I/30)*b*c^2*d^3*x^5 - (I/6)*a*c^3*d^3*x^6 - (((11*I)/12)*b*d^
3*ArcTan[c*x])/c^3 + (b*d^3*x^3*ArcTan[c*x])/3 + ((3*I)/4)*b*c*d^3*x^4*ArcTan[c*x] - (3*b*c^2*d^3*x^5*ArcTan[c
*x])/5 - (I/6)*b*c^3*d^3*x^6*ArcTan[c*x] + (7*b*d^3*Log[1 + c^2*x^2])/(15*c^3)

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fricas [A]  time = 0.44, size = 188, normalized size = 0.98 \[ \frac {-60 i \, a c^{6} d^{3} x^{6} - 12 \, {\left (18 \, a - i \, b\right )} c^{5} d^{3} x^{5} + {\left (270 i \, a + 54 \, b\right )} c^{4} d^{3} x^{4} + 10 \, {\left (12 \, a - 11 i \, b\right )} c^{3} d^{3} x^{3} - 168 \, b c^{2} d^{3} x^{2} + 330 i \, b c d^{3} x + 333 \, b d^{3} \log \left (\frac {c x + i}{c}\right ) + 3 \, b d^{3} \log \left (\frac {c x - i}{c}\right ) + {\left (30 \, b c^{6} d^{3} x^{6} - 108 i \, b c^{5} d^{3} x^{5} - 135 \, b c^{4} d^{3} x^{4} + 60 i \, b c^{3} d^{3} x^{3}\right )} \log \left (-\frac {c x + i}{c x - i}\right )}{360 \, c^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(d+I*c*d*x)^3*(a+b*arctan(c*x)),x, algorithm="fricas")

[Out]

1/360*(-60*I*a*c^6*d^3*x^6 - 12*(18*a - I*b)*c^5*d^3*x^5 + (270*I*a + 54*b)*c^4*d^3*x^4 + 10*(12*a - 11*I*b)*c
^3*d^3*x^3 - 168*b*c^2*d^3*x^2 + 330*I*b*c*d^3*x + 333*b*d^3*log((c*x + I)/c) + 3*b*d^3*log((c*x - I)/c) + (30
*b*c^6*d^3*x^6 - 108*I*b*c^5*d^3*x^5 - 135*b*c^4*d^3*x^4 + 60*I*b*c^3*d^3*x^3)*log(-(c*x + I)/(c*x - I)))/c^3

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \mathit {sage}_{0} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(d+I*c*d*x)^3*(a+b*arctan(c*x)),x, algorithm="giac")

[Out]

sage0*x

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maple [A]  time = 0.03, size = 197, normalized size = 1.03 \[ -\frac {i c^{3} d^{3} a \,x^{6}}{6}-\frac {3 c^{2} d^{3} a \,x^{5}}{5}+\frac {3 i c \,d^{3} a \,x^{4}}{4}+\frac {d^{3} a \,x^{3}}{3}-\frac {i c^{3} d^{3} b \arctan \left (c x \right ) x^{6}}{6}-\frac {3 c^{2} d^{3} b \arctan \left (c x \right ) x^{5}}{5}+\frac {3 i c \,d^{3} b \arctan \left (c x \right ) x^{4}}{4}+\frac {d^{3} b \arctan \left (c x \right ) x^{3}}{3}+\frac {11 i b \,d^{3} x}{12 c^{2}}+\frac {i b \,c^{2} d^{3} x^{5}}{30}+\frac {3 b c \,d^{3} x^{4}}{20}-\frac {11 i b \,d^{3} x^{3}}{36}-\frac {7 b \,d^{3} x^{2}}{15 c}+\frac {7 b \,d^{3} \ln \left (c^{2} x^{2}+1\right )}{15 c^{3}}-\frac {11 i b \,d^{3} \arctan \left (c x \right )}{12 c^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(d+I*c*d*x)^3*(a+b*arctan(c*x)),x)

[Out]

-1/6*I*c^3*d^3*a*x^6-3/5*c^2*d^3*a*x^5+3/4*I*c*d^3*a*x^4+1/3*d^3*a*x^3-1/6*I*c^3*d^3*b*arctan(c*x)*x^6-3/5*c^2
*d^3*b*arctan(c*x)*x^5+3/4*I*c*d^3*b*arctan(c*x)*x^4+1/3*d^3*b*arctan(c*x)*x^3+11/12*I*b*d^3*x/c^2+1/30*I*b*c^
2*d^3*x^5+3/20*b*c*d^3*x^4-11/36*I*b*d^3*x^3-7/15*b*d^3*x^2/c+7/15*b*d^3*ln(c^2*x^2+1)/c^3-11/12*I*b*d^3*arcta
n(c*x)/c^3

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maxima [A]  time = 0.42, size = 242, normalized size = 1.27 \[ -\frac {1}{6} i \, a c^{3} d^{3} x^{6} - \frac {3}{5} \, a c^{2} d^{3} x^{5} + \frac {3}{4} i \, a c d^{3} x^{4} - \frac {1}{90} i \, {\left (15 \, x^{6} \arctan \left (c x\right ) - c {\left (\frac {3 \, c^{4} x^{5} - 5 \, c^{2} x^{3} + 15 \, x}{c^{6}} - \frac {15 \, \arctan \left (c x\right )}{c^{7}}\right )}\right )} b c^{3} d^{3} - \frac {3}{20} \, {\left (4 \, x^{5} \arctan \left (c x\right ) - c {\left (\frac {c^{2} x^{4} - 2 \, x^{2}}{c^{4}} + \frac {2 \, \log \left (c^{2} x^{2} + 1\right )}{c^{6}}\right )}\right )} b c^{2} d^{3} + \frac {1}{3} \, a d^{3} x^{3} + \frac {1}{4} i \, {\left (3 \, x^{4} \arctan \left (c x\right ) - c {\left (\frac {c^{2} x^{3} - 3 \, x}{c^{4}} + \frac {3 \, \arctan \left (c x\right )}{c^{5}}\right )}\right )} b c d^{3} + \frac {1}{6} \, {\left (2 \, x^{3} \arctan \left (c x\right ) - c {\left (\frac {x^{2}}{c^{2}} - \frac {\log \left (c^{2} x^{2} + 1\right )}{c^{4}}\right )}\right )} b d^{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(d+I*c*d*x)^3*(a+b*arctan(c*x)),x, algorithm="maxima")

[Out]

-1/6*I*a*c^3*d^3*x^6 - 3/5*a*c^2*d^3*x^5 + 3/4*I*a*c*d^3*x^4 - 1/90*I*(15*x^6*arctan(c*x) - c*((3*c^4*x^5 - 5*
c^2*x^3 + 15*x)/c^6 - 15*arctan(c*x)/c^7))*b*c^3*d^3 - 3/20*(4*x^5*arctan(c*x) - c*((c^2*x^4 - 2*x^2)/c^4 + 2*
log(c^2*x^2 + 1)/c^6))*b*c^2*d^3 + 1/3*a*d^3*x^3 + 1/4*I*(3*x^4*arctan(c*x) - c*((c^2*x^3 - 3*x)/c^4 + 3*arcta
n(c*x)/c^5))*b*c*d^3 + 1/6*(2*x^3*arctan(c*x) - c*(x^2/c^2 - log(c^2*x^2 + 1)/c^4))*b*d^3

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mupad [B]  time = 0.83, size = 174, normalized size = 0.91 \[ -\frac {\frac {d^3\,\left (-84\,b\,\ln \left (c^2\,x^2+1\right )+b\,\mathrm {atan}\left (c\,x\right )\,165{}\mathrm {i}\right )}{180}+\frac {7\,b\,c^2\,d^3\,x^2}{15}-\frac {b\,c\,d^3\,x\,11{}\mathrm {i}}{12}}{c^3}+\frac {d^3\,\left (60\,a\,x^3+60\,b\,x^3\,\mathrm {atan}\left (c\,x\right )-b\,x^3\,55{}\mathrm {i}\right )}{180}-\frac {c^3\,d^3\,\left (a\,x^6\,30{}\mathrm {i}+b\,x^6\,\mathrm {atan}\left (c\,x\right )\,30{}\mathrm {i}\right )}{180}+\frac {c\,d^3\,\left (a\,x^4\,135{}\mathrm {i}+27\,b\,x^4+b\,x^4\,\mathrm {atan}\left (c\,x\right )\,135{}\mathrm {i}\right )}{180}-\frac {c^2\,d^3\,\left (108\,a\,x^5+108\,b\,x^5\,\mathrm {atan}\left (c\,x\right )-b\,x^5\,6{}\mathrm {i}\right )}{180} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(a + b*atan(c*x))*(d + c*d*x*1i)^3,x)

[Out]

(d^3*(60*a*x^3 - b*x^3*55i + 60*b*x^3*atan(c*x)))/180 - ((d^3*(b*atan(c*x)*165i - 84*b*log(c^2*x^2 + 1)))/180
+ (7*b*c^2*d^3*x^2)/15 - (b*c*d^3*x*11i)/12)/c^3 - (c^3*d^3*(a*x^6*30i + b*x^6*atan(c*x)*30i))/180 + (c*d^3*(a
*x^4*135i + 27*b*x^4 + b*x^4*atan(c*x)*135i))/180 - (c^2*d^3*(108*a*x^5 - b*x^5*6i + 108*b*x^5*atan(c*x)))/180

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sympy [A]  time = 4.90, size = 316, normalized size = 1.65 \[ - \frac {i a c^{3} d^{3} x^{6}}{6} - \frac {7 b d^{3} x^{2}}{15 c} + \frac {11 i b d^{3} x}{12 c^{2}} - \frac {b d^{3} \left (- \frac {\log {\left (310 b c d^{3} x - 310 i b d^{3} \right )}}{120} - \frac {209 \log {\left (310 b c d^{3} x + 310 i b d^{3} \right )}}{280}\right )}{c^{3}} - x^{5} \left (\frac {3 a c^{2} d^{3}}{5} - \frac {i b c^{2} d^{3}}{30}\right ) - x^{4} \left (- \frac {3 i a c d^{3}}{4} - \frac {3 b c d^{3}}{20}\right ) - x^{3} \left (- \frac {a d^{3}}{3} + \frac {11 i b d^{3}}{36}\right ) + \left (- \frac {b c^{3} d^{3} x^{6}}{12} + \frac {3 i b c^{2} d^{3} x^{5}}{10} + \frac {3 b c d^{3} x^{4}}{8} - \frac {i b d^{3} x^{3}}{6}\right ) \log {\left (i c x + 1 \right )} - \frac {\left (- 70 b c^{6} d^{3} x^{6} + 252 i b c^{5} d^{3} x^{5} + 315 b c^{4} d^{3} x^{4} - 140 i b c^{3} d^{3} x^{3} - 150 b d^{3}\right ) \log {\left (- i c x + 1 \right )}}{840 c^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(d+I*c*d*x)**3*(a+b*atan(c*x)),x)

[Out]

-I*a*c**3*d**3*x**6/6 - 7*b*d**3*x**2/(15*c) + 11*I*b*d**3*x/(12*c**2) - b*d**3*(-log(310*b*c*d**3*x - 310*I*b
*d**3)/120 - 209*log(310*b*c*d**3*x + 310*I*b*d**3)/280)/c**3 - x**5*(3*a*c**2*d**3/5 - I*b*c**2*d**3/30) - x*
*4*(-3*I*a*c*d**3/4 - 3*b*c*d**3/20) - x**3*(-a*d**3/3 + 11*I*b*d**3/36) + (-b*c**3*d**3*x**6/12 + 3*I*b*c**2*
d**3*x**5/10 + 3*b*c*d**3*x**4/8 - I*b*d**3*x**3/6)*log(I*c*x + 1) - (-70*b*c**6*d**3*x**6 + 252*I*b*c**5*d**3
*x**5 + 315*b*c**4*d**3*x**4 - 140*I*b*c**3*d**3*x**3 - 150*b*d**3)*log(-I*c*x + 1)/(840*c**3)

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